3p^2=735

Solution for 3p^2=735 equation:

3p^2=735

We move all terms to the left:

3p^2-(735)=0

a = 3; b = 0; c = -735;
Δ = b2-4ac
Δ = 02-4·3·(-735)
Δ = 8820
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8820}=\sqrt{1764*5}=\sqrt{1764}*\sqrt{5}=42\sqrt{5}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42\sqrt{5}}{2*3}=\frac{0-42\sqrt{5}}{6}
=-\frac{42\sqrt{5}}{6}
=-7\sqrt{5}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42\sqrt{5}}{2*3}=\frac{0+42\sqrt{5}}{6}
=\frac{42\sqrt{5}}{6}
=7\sqrt{5}
$